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Analysis of Lead Chloride (PbCl₂)

Class 12 Chemistry Practical

Aim

To analyse the given inorganic salt for one acidic and one basic radical.

Preliminary Test

ExperimentObservationInference
Physical examinationWhite solid; odourlessNot acetate
SolubilitySparingly soluble in cold water; soluble in hot waterCharacteristic of PbCl₂
Dry heatingMay melt; no sublimate of NH₄Cl; no brown NO₂Not ammonium chloride / lead nitrate
Dilute H₂SO₄White ppt of PbSO₄ may form; no CO₂Not carbonate
Conc. H₂SO₄HCl gas (from chloride) on heatingCl⁻ may be present
Flame testNo apple-green / brick-redNot Ba / Ca

Test of Anion (Cl⁻)

ExperimentObservationInference
Heat a pinch of salt with conc. H₂SO₄Colourless gas with a pungent smell; dense white fumes with NH₄OHCl⁻ may be present
Confirmatory Tests
MnO₂ / conc. H₂SO₄
Heat the salt with conc. H₂SO₄ and a pinch of MnO₂
Greenish-yellow chlorine gas is evolvedCl⁻ is indicated
Silver nitrate
Acidify the soda extract with dilute HNO₃ and add AgNO₃, then NH₄OH
Curdy white ppt of AgCl, soluble in NH₄OH, reappears with dilute HNO₃Cl⁻ is confirmed
Chromyl chloride
Heat salt + K₂Cr₂O₇ + conc. H₂SO₄. Pass vapours into NaOH; acidify with acetic acid and add lead acetate
Yellow chromyl chloride vapours; yellow ppt of PbCrO₄Cl⁻ is confirmed (chromyl chloride test)

Ionic equations

  • NaCl + H₂SO₄ (conc.) → NaHSO₄ + HCl ↑
  • MnO₂ + 4HCl → MnCl₂ + Cl₂ ↑ + 2H₂O
  • Ag⁺ + Cl⁻ → AgCl ↓ (white)
  • AgCl + 2NH₄OH → [Ag(NH₃)₂]Cl + 2H₂O

Test of Cation (Pb²⁺)

ExperimentObservationInference
To the original solution add dilute HClWhite ppt of PbCl₂, soluble in hot water, reappears on coolingGroup I (Pb²⁺) may be present
Confirmatory Tests
Potassium iodide
To the hot solution of the ppt add KI
Yellow ppt of PbI₂ (golden spangles on cooling)Pb²⁺ is confirmed
Potassium chromate
To the acidified solution add K₂CrO₄
Yellow ppt of PbCrO₄, insoluble in acetic acidPb²⁺ is confirmed

Ionic equations

  • Pb²⁺ + 2Cl⁻ → PbCl₂ ↓
  • Pb²⁺ + 2I⁻ → PbI₂ ↓ (yellow)
  • Pb²⁺ + CrO₄²⁻ → PbCrO₄ ↓ (yellow)

Result

The given salt contains Pb²⁺ as the cation (basic radical) and Cl⁻ as the anion (acidic radical). The salt is Lead Chloride (PbCl₂).

Precautions

  1. Use small quantities of salt and reagents; do not use excess.
  2. Keep the mouth of the test tube away from the face while heating.
  3. Use freshly prepared FeSO₄ for the brown ring test.
  4. Nessler’s reagent is toxic (mercury); handle with care and do not pipette by mouth.

Viva voce

  1. Why dissolve in hot water?

    Solubility of PbCl₂ rises sharply with temperature.

  2. Why golden spangles with KI?

    PbI₂ crystallises as shining yellow plates.

  3. Why chromyl chloride can still work?

    The salt contains chloride.

  4. How is this different from NH₄Cl?

    No ammoniacal smell, no sublimation, Group I lead tests instead of Nessler.

  5. Why might original solution be made in hot water?

    Cold water does not dissolve enough PbCl₂.

  6. Why yellow with chromate?

    PbCrO₄.

  7. Why not Group II after this?

    Lead is already confirmed in Group I (though Pb²⁺ can also ppt as PbS later if missed).

  8. Is the formula Pb(Cl)₂?

    No. Write PbCl₂.