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Analysis of Ammonium Carbonate ((NH₄)₂CO₃)

Class 12 Chemistry Practical

Aim

To analyse the given inorganic salt for one acidic and one basic radical.

Preliminary Test

ExperimentObservationInference
Physical examinationWhite solid; ammoniacal smellAmmonium salt
SolubilitySoluble in waterUnlike CaCO₃ / BaCO₃, ammonium carbonate dissolves
Dry heatingNH₃ and CO₂ evolved; salt may disappear (volatile)Ammonium carbonate
Dilute H₂SO₄Brisk effervescence of CO₂; lime water milkyCO₃²⁻ present
Conc. H₂SO₄CO₂ evolved; no halide fumesCarbonate, not halide
Flame testNo characteristic colourNot Ba / Sr / Ca

Test of Anion (CO₃²⁻)

ExperimentObservationInference
Add dilute H₂SO₄ (or dilute HCl) to the saltBrisk effervescence; colourless, odourless gasCO₃²⁻ may be present
Confirmatory Test
Lime water
Pass the gas through lime water. Continue passing in excess
Lime water turns milky; milkiness disappears on excess CO₂CO₃²⁻ is confirmed

Ionic equations

  • CO₃²⁻ + 2H⁺ → CO₂ ↑ + H₂O
  • Ca(OH)₂ + CO₂ → CaCO₃ ↓ (milky) + H₂O
  • CaCO₃ + CO₂ + H₂O → Ca(HCO₃)₂ (milkiness disappears)

Test of Cation (NH₄⁺)

ExperimentObservationInference
Heat the salt with NaOH solutionAmmoniacal smell; gas turns red litmus blueNH₄⁺ may be present (Group 0)
Bring a glass rod dipped in conc. HCl near the mouth of the tubeDense white fumes of NH₄ClNH₄⁺ may be present
Confirmatory Test
Nessler’s reagent
Pass the gas into Nessler’s reagent (K₂[HgI₄] in KOH)
Brown colouration or brown ppt of basic mercury(II) amidoiodideNH₄⁺ is confirmed. Stop cation analysis here for ammonium salts.

Ionic equations

  • NH₄⁺ + OH⁻ → NH₃ ↑ + H₂O
  • NH₃ + HCl → NH₄Cl (white fumes)
  • 2K₂[HgI₄] + 3KOH + NH₃ → H₂N–Hg–O–Hg–I ↓ + 7KI + 2H₂O

Result

The given salt contains NH₄⁺ as the cation (basic radical) and CO₃²⁻ as the anion (acidic radical). The salt is Ammonium Carbonate ((NH₄)₂CO₃).

Precautions

  1. Use small quantities of salt and reagents; do not use excess.
  2. Keep the mouth of the test tube away from the face while heating.
  3. Use freshly prepared FeSO₄ for the brown ring test.
  4. Nessler’s reagent is toxic (mercury); handle with care and do not pipette by mouth.

Viva voce

  1. Why brisk effervescence with dilute acid?

    Carbonate + acid → CO₂.

  2. How do you distinguish CO₂ from SO₂?

    SO₂ has a burning-sulphur smell and decolourises acidified KMnO₄ / K₂Cr₂O₇; CO₂ does not.

  3. Why is this salt soluble unlike chalk?

    Alkali and ammonium carbonates are soluble; Group II carbonates are not.

  4. Why Nessler after NaOH?

    NaOH liberates NH₃; Nessler confirms it.

  5. Why Group 0 first?

    NH₄⁺ would interfere later (NH₄OH is a group reagent). Always test ammonium first.

  6. What happens on strong heating?

    Ammonium carbonate decomposes completely to gases.

  7. Why milkiness of lime water?

    Insoluble CaCO₃.

  8. Can sulphite give lime water milky?

    SO₂ also turns lime water milky (CaSO₃). Smell and KMnO₄ distinguish it.

अमोनियम कार्बोनेट (हिन्दी में)

नमक: अमोनियम कार्बोनेट। तनु अम्ल से तेज़ बुदबुदाहट (CO₂), चूने का पानी दूधिया।

क्षारीय मूलक अमोनियम है। NaOH और नैस्लर। वर्ग I-VI आगे नहीं चलाते।

यह नमक जल में घुलनशील है, कैल्शियम कार्बोनेट (चाक) नहीं।